LSSTApplications  18.0.0+106,18.0.0+50,19.0.0,19.0.0+1,19.0.0+10,19.0.0+11,19.0.0+13,19.0.0+17,19.0.0+2,19.0.0-1-g20d9b18+6,19.0.0-1-g425ff20,19.0.0-1-g5549ca4,19.0.0-1-g580fafe+6,19.0.0-1-g6fe20d0+1,19.0.0-1-g7011481+9,19.0.0-1-g8c57eb9+6,19.0.0-1-gb5175dc+11,19.0.0-1-gdc0e4a7+9,19.0.0-1-ge272bc4+6,19.0.0-1-ge3aa853,19.0.0-10-g448f008b,19.0.0-12-g6990b2c,19.0.0-2-g0d9f9cd+11,19.0.0-2-g3d9e4fb2+11,19.0.0-2-g5037de4,19.0.0-2-gb96a1c4+3,19.0.0-2-gd955cfd+15,19.0.0-3-g2d13df8,19.0.0-3-g6f3c7dc,19.0.0-4-g725f80e+11,19.0.0-4-ga671dab3b+1,19.0.0-4-gad373c5+3,19.0.0-5-ga2acb9c+2,19.0.0-5-gfe96e6c+2,w.2020.01
LSSTDataManagementBasePackage
Relationship.h
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1 /*
2  * LSST Data Management System
3  * Copyright 2014-2016 AURA/LSST.
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5  * This product includes software developed by the
6  * LSST Project (http://www.lsst.org/).
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22 
23 #ifndef LSST_SPHGEOM_RELATIONSHIP_H_
24 #define LSST_SPHGEOM_RELATIONSHIP_H_
25 
26 #include <bitset>
27 
30 
31 namespace lsst {
32 namespace sphgeom {
33 
36 
38 static constexpr Relationship DISJOINT(1);
39 
44 static constexpr Relationship INTERSECTS(0);
45 
47 static constexpr Relationship CONTAINS(2);
48 
50 static constexpr Relationship WITHIN(4);
51 
56  // If A is disjoint from B, then B is disjoint from A. But if A contains B
57  // then B is within A, so the corresponding bits must be swapped.
58  return (r & DISJOINT) | ((r & CONTAINS) << 1) | ((r & WITHIN) >> 1);
59 }
60 
61 }} // namespace lsst::sphgeom
62 
63 #endif // LSST_SPHGEOM_RELATIONSHIP_H_
Relationship invert(Relationship r)
Given the relationship between two sets A and B (i.e.
Definition: Relationship.h:55
A base class for image defects.
STL class.